ABC answer

Solution a:

3194 + ABC = 222(A + B + C)

14 X 222 + 86 + ABC = 222(A + B + C)

86 + ABC = k222

when k = 2

ABC = 358

Method 2:

ABC = 358

5 one hundred addition to: A + 2 b + 2 c

Ten to nine by 3194 so ten to one hundred carry not 4, of course, also can't be 1 or 0, no that number is too small.Then we get:

A + 2 b + c = 28 (1) or 2

A + 2B + 2C = 29 (2)

And has five all together also can only for 2 or 3:

2 a + 2 b + C = 24, or (3)

2A + 2B + C = 34 (4)

From the known C an even number

If (4) set up separately in (4) - (1) = 5

A - C = 5 or

(4) - (2) = 6

A - C = 6

C = 2 A = 7 or A = 8

C = 4 A = 9

Into all wrong.Therefore, (4).

Five of ten and a + B + 2 c = 27 (5)

Or 2 a + B + 2 c = 37 (6)

If for 37 (6) - (3) = C - B = 13 not stand!(Psychological tests /test/)

(1), (3) (5) or (2), (3), (5) solution, calculus can!